flush-shown: a flush may name a member an earlier line showed (kills the seen dedup survivor)
Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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@ -2591,6 +2591,16 @@ fn a_flush_alone_may_not_name_a_stranger_or_settle_a_closed_item() {
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assert_eq!(outcome_of(&rig, &id), Some(ResolutionOutcome::Recorded { reason: "integrated".into() }));
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}
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#[test]
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fn a_flush_alone_may_name_a_member_an_earlier_line_showed_though_no_mind_or_operator() {
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let guest = "@guest:chat";
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let rig = Rig::new(vec![delivery(1, "swarm", guest, "hello")], &[says(&[("swarm", "hi")]), reply(&[], json!([keeps("Did", "Greeted the guest", &[guest])]), json!([]), json!(null))]);
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rig.cap.set(u64::try_from(ROTATE_MARGIN_S).unwrap());
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assert_eq!(failure_of(rig.go()), None);
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assert_eq!(last_outcome(&rig), "answered");
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assert_eq!(memories(&rig).len(), 1);
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}
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/// 3 and 4 are told; a poll writes 5 while their turn runs; their result is refused; 5's echo opens the next
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/// turn, and 5's result is refused too before a poll falls due (a turn shorter than the poll). Both refused
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/// batches are told again together, as one line, and the one answer acks through 5.
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