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Sim speed: tests for the survivors Stryker found (thruster turn, tilted draw, exact step)

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DrawAhead.Rotation delegates to Turned(pose, angle) so the turn is testable on a tilted pose, where the flat Duel poses make the quaternion product's off-axis terms vanish. Unverified at this commit.

Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
This commit is contained in:
Meta Vens 2026-10-08 21:00:16 +02:00
commit 090b6d18dc
2 changed files with 56 additions and 3 deletions
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Assets/Scripts/ServerShared/DrawAhead.cs
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@ -14,13 +14,15 @@ public static class DrawAhead
entity.Position + float3(entity.Velocity.x, 0, entity.Velocity.y) * lead;
// The ship's rotation turned about its own up axis by the rate its last step turned, for lead seconds.
public static quaternion Rotation(Ship ship, float lead)
public static quaternion Rotation(Ship ship, float lead) => Turned(ship.Rotation, ship.TurnRate * lead);
// q turned about its own up axis by the angle, in the sense Direction turns for a positive TurnRate.
public static quaternion Turned(quaternion q, float angle)
{
var q = ship.Rotation;
var u = float3(q.x, q.y, q.z);
var up = float3(0, 1, 0);
up += 2 * (q.w * cross(u, up) + cross(u, cross(u, up)));
var half = ship.TurnRate * lead * .5f;
var half = angle * .5f;
var s = sin(half);
var t = new quaternion(up.x * s, up.y * s, up.z * s, cos(half));
// Hamilton product t * q: CultMath carries no quaternion product (a gap in CultMath, not filled here).